According to Ohms Law, R = V/I, which gives us an equivalent resistance of
377V / 187mA = 2kΩ
The amount of heat produced is
P = VI = (377V)(187mA) = 70W
So if we were to replace the Bassman's preamps, phase inverter, and push-pull power stage by a big 2kΩ resistor capable of handling 70 watts, then the 5F6-A power supply would sag to 377V.
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