Here is the classic James Tone Stack as used, for example, in the 120-watt Orange Graphic.

To keep the mathematics from becoming overwhelming, we'll make a few assumptions. First, we'll assume that the driving circuit has an output impedance of zero. For a low-impedance driver like a cathode follower, this is a highly-accurate assumption. A typical 12AX7 voltage amplifier, however, has an output impedance of almost 40k, which reduces the accuracy of our formulas. Second, we'll assume tone control resistances are infinite, because typical 1M controls are much greater than the other resistor values in the circuit. Finally, we'll assume that the tone stack output drives an infinite input impedance. Typically the input impedance to the next stage is at least 1M.

These assumptions make it easier to design the James tone stack and calculate the required parts values. Once the circuit is finalized we can test the results under real circuit conditions.

Let's begin by setting the bass and treble controls at maximum. This shorts **C _{1}** and connects

**C _{3}** is smaller than

Because we're driving an open circuit, there is no current through **R _{3}** and by Ohm's Law there is no voltage across it. Thus we can treat it as a short circuit, giving us a classic voltage divider where

(If the variable "**s**" looks unfamiliar, please see our
tutorial on Laplace notation.) With some re-arranging we get the following formula suitable for creating a Bode magnitude plot:

where

There is a zero at **s = -b** and a pole at **s = -a**. Let's look at the extremes of frequency. At DC, where **s = 0**, we get **H(s) = 1**, so there is no attenuation. As the frequency goes to infinity we get

This makes sense, because at very high frequencies the capacitor is a short circuit and we get just a voltage divider formed by **R _{1}** and

Above this frequency the response transitions to its midrange value, decreasing at a rate of 6dB per octave (20dB per decade) until we reach the bass-midrange transition frequency based on the zero:

Here we are arriving at midrange, and the response is only 3dB above its final midrange value of

Let's say all this once more and then introduce some hard numbers to make it even more clear. We have the bass control set to maximum, so we have no attenuation at very low frequencies. At the first transition frequency attenuation begins, ultimately decreasing at a rate of 20dB per decade until we reach the bass-midrange transition frequency where the gain levels off at a steady midrange attenuation value that lasts until we reach treble frequencies and **C _{3}** starts conducting significant current.

Now for some hard numbers.

The Orange Graphic uses **R _{1} = 100k**,

which is 59 Hz, the gain has fallen by 3dB and is starting to decrease at a rate of 20dB per decade. It finally starts leveling off at the bass-midrange transition frequency of

which is 329Hz. At this point the gain is 3dB above its midrange value of -15dB.

Now we are ready to draw the Bode magnitude plot for low and midrange frequencies with the bass control at maximum. For the pole we draw a horizontal line at 0dB until we reach the transition frequency of 59Hz. Then we draw a line sloping downward at the rate of 20dB per decade. For the zero we also draw a horizontal line at 0dB until we reach 329Hz, where we then draw a line sloping upward at 20dB per decade. The actual frequency response is very close to the sum of these two approximations. Here is the plot.

The approximate pole response and the approximate zero response are the dotted and dashed lines, respectively. The actual response, which includes the 3dB differences at the transition points, is the solid curve.

At high frequencies **C _{2}** acts as a short circuit and

The frequency response is

This makes sense, because at DC, where **s = 0**, the response is

The capacitor is an open circuit at DC, there is no current through **R _{3}** and thus no voltage drop across it. Thus the output voltage is equal to the input voltage reduced in magnitude by the voltage divider formed by

At extremely high frequencies, as **s** goes to infinity, the response becomes

This also makes sense, because at infinitely high frequencies the capacitor is a short circuit.

When **R _{3} = R_{1}**, as in the Orange Graphic and many other designs, the response becomes

where

From these formulas we see that there is a gain of **b/a** and transition frequencies for a pole at **-a** and a zero at **-b**:

The second represents the midrange-treble transition frequency and the first represents a transition to zero attenuation at high treble frequencies. The gain thus begins at the midrange level created by the voltage divider formed by **R _{1}** and

The Orange Graphic uses **C _{3} = 1500pF**, for which the transition frequencies are 162Hz and 900Hz. Here is the Bode magnitude plot.

Here are the two Bode plots superimposed. The bass-to-midrange plot is only valid at low frequencies and the midrange-to-treble plot is only valid at high frequencies. The complete response is a gradual combining of the two plots.

Our calculations assume an ideal source, an ideal load, and infinite-impedance tone controls. Here is the actual response using Electronics Workbench Multisim®. The plot assumes 1M tone controls, a driving circuit output impedance of 49k (using the Orange Graphic's 220k plate resistor), and a driven circuit input impedance of 1M.

(The horizontal axis is a log scale of frequency from 10Hz to 10kHz and the vertical scale is from -20dB to 0dB.) We see that the real world impedances of the driving and driven circuits cause additional attenuation, but otherwise there are no surprises. Maximum attenuation occurs right where we expect.

When the tone controls are set to minimum we get this circuit:

which has this frequency response:

When **R _{3} = R_{1}** then this simplifies, at least slightly, to

For reasonable values, in particular when **R _{1}** and

where

At DC, where **s = 0**, and at infinitely high frequencies, where **s** approaches infinity, the equation shows that the response is zero, which makes sense when the controls are at minimum because at DC the capacitor **C _{1}** is an open circuit and at the extremes of treble capacitor

There is a zero at **s = 0** and there are poles at **s = -a _{1}** and

At extremely low frequencies, because of the zero, gain increases at a rate of 20dB per decade. It would ultimately reach 0dB at a frequency of

but at the first transition frequency a pole kicks in and the gain starts leveling out. At the second transition frequency the other pole causes the gain to drop 3dB. Thereafter gain decreases further at the rate of 20dB per decade.

For Orange Graphic's **C _{4} = 0.01uF** the lower transition frequency is 130Hz. For

Here is the response using Electronics Workbench Multisim®. (1M tone controls, a driving circuit output impedance of 49k, and a driven circuit input impedance of 1M.)

(The vertical scale is -50dB to 0dB.) Here we see that under real circuit conditions the attenuation is less dramatic and shifted downward in frequency.

To convert our analysis into a practical design procedure we need to translate the equations that determine the frequency response based on parts values into equations that determine parts values based on the desired frequency response. We take that step and put the formulas to practical use here:

The James Tone Stack: Creating Your Own Design.

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